4.35=4.1x^2

Solution for 4.35=4.1x^2 equation:

4.35=4.1x^2

We move all terms to the left:

4.35-(4.1x^2)=0

We get rid of parentheses

-4.1x^2+4.35=0

a = -4.1; b = 0; c = +4.35;
Δ = b2-4ac
Δ = 02-4·(-4.1)·4.35
Δ = 71.34
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{71.34}}{2*-4.1}=\frac{0-\sqrt{71.34}}{-8.2}
=-\frac{\sqrt{}}{-8.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{71.34}}{2*-4.1}=\frac{0+\sqrt{71.34}}{-8.2}
=\frac{\sqrt{}}{-8.2}
$